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*2016 Dec 7*

Find the equation of the graph of a parabola that is neither vertical or horizontal.

It is commonly known that a parabola is the locus of all points equidistant from a point, called the *focus*, and a line, called the *directrix*. The quadratic function represents a parabola with a horizontal directrix, and the square root function can represent half of a parabola with a vertical directrix. Given a horizontal or vertical directrix, it is easy to write the equation of the parabola, since the distance of a point on the parabola from the focus can be found by the distance formula and the distance of a point on the parabola from a horizontal or vertical line can be found by the absolute value of the difference between the abscissa or ordinate of the point on the parabola and the y- or x-value of the horizontal or vertical line. However, now that we have a formula for the distance between a point and *any* line with defined nonzero slope, we can create a parabola that is tilted at an angle. The way to do this would be to choose a directrix line $y=mx+b$ and a focus $(x_0, y_0)$, and the equation of the parabola would be

Let's try an example: the parabola with focus $(1,1)$ and directrix $y=-x$. First we must set up our equation:

And now we must simplify. To begin, we square both sides.

Then we expand the binomials.

Now that we have this in $ax^2+bx+c$ form as a quadratic of y, we can solve it for y in terms of x using the quadratic formula.

In this case, $y$ is not a function of $x$ because of the plus-or-minus, but the parabola can be represented as the two functions $2+x+2\sqrt{2x}$ and $2+x-2\sqrt{2x}$ together. Here is a graph of the parabola, along with its focus and directrix:

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